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leetcode---Factorial Trailing Zeroes

2016-04-09 23:21 363 查看
Given an integer n, return the number of trailing zeroes in n!.

Note: Your solution should be in logarithmic time complexity.

class Solution {
public:
int trailingZeroes(int n)
{
if(n == 0)
return 0;
int c5 = 0;
while(n)
{
c5 += n/5;
n /= 5;
}
return c5;
}
};
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