HashMap<String, ArrayList<Integer>>用法

import java.util.ArrayList;

import java.util.HashMap;

import java.util.Iterator;

import java.util.List;

/*public class hashmap {

*//**

* @param args

*//*

public static void main(String[] args) {

// TODO Auto-generated method stub

HashMap<String, ArrayList<Integer>>hash=new HashMap<String, ArrayList<Integer>>();

String key="aa";

hash.put(key, hash.get(key));

//hash.get("aa").add(22);

System.out.println(hash.get(key).add(2));

}

}*/

public class Test {

public static ArrayList<String> listA=new ArrayList<String>();

public static ArrayList<String> listB=new ArrayList<String>();

public static HashMap<Integer,ArrayList<String>> hashmapA=new HashMap<Integer,ArrayList<String>>();

public static HashMap<Integer,ArrayList<String>> hashmapB=new HashMap<Integer,ArrayList<String>>();

public static void main(String args[]) {

listA.add("AAA");

listA.add("aaa");

listA.add("AAAAA");

listA.add("bbbb");

listA.add("kkkkk");

listB.add("OOOO");

listB.add("llll");

listB.add("pppp");

listB.add("ppppp");

listB.add("nnnn");

hashmapA.put(1, listA);

hashmapA.put(2, listB);

System.out.println(hashmapA);

for(Iterator i = hashmapA.keySet().iterator();i.hasNext();)

{

Integer interger = (Integer)i.next();

List<String> list = hashmapA.get(interger);

for(String s: list)

{

System.out.println(s);

}

}

}

}

输出结果为

{1=[AAA, aaa, AAAAA, bbbb, kkkkk], 2=[OOOO, llll, pppp, ppppp, nnnn]}

AAA

aaa

AAAAA

bbbb

kkkkk

OOOO

llll

pppp

ppppp

nnnn

{1=[AAA, aaa, AAAAA, bbbb, kkkkk], 2=[OOOO, llll, pppp, ppppp, nnnn]}

AAA

aaa

AAAAA

bbbb

kkkkk

OOOO

llll

pppp

ppppp

nnnn

{1=[AAA, aaa, AAAAA, bbbb, kkkkk], 2=[OOOO, llll, pppp, ppppp, nnnn]}

AAA

aaa

AAAAA

bbbb

kkkkk

OOOO

llll

pppp

ppppp

nnnn