您的位置:首页 > 其它

LeetCode Remove Element

2016-04-06 19:02 239 查看
Given an array and a value, remove all instances of that value in place and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

Example:

Given input array nums = [3,2,2,3], val = 3

Your function should return length = 2, with the first two elements of nums being 2.

/**
* 去除数组中等于给定的数
* 新数组中元素个数小于等于原数组
* Created by ustc-lezg on 16/4/6.
*/
public class Solution {

public int removeElement(int[] nums, int val) {
int index = 0;
for (int i = 0, len = nums.length; i < len; i++) {
if (nums[i] != val) {
nums[index++] = nums[i];
}
}
return index;
}

}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  leetcode