leetCode之旅（14）-Number of 1 Bits

题目描述：

Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight).

For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function should return 3.

Credits:

Special thanks to @ts for adding this problem and creating all test cases.

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思路分析：

给定一个无符号整数。求整它转化为二进制以后，里面的1的个数

代码：

public class Solution {

// you need to treat n as an unsigned value
public int hammingWeight(int n) {
//用来计数
int count = 0;
for(int i = 0;i < 32;i++){
if((n&1) != 0){
count++;
}
n = n>>1;
}
return count;
}

} ##