Rain

问题及代码：

/*
*Copyright (c)2015,大连东软信息学院
*All rights reserved.
*文件名称：rain.c
*作 者：陈振
*完成日期：2016年3月12日
*版 本 号： v1.0
*问题描述：针对若干年的降水量数据，计算年降水量，年降水平均量，以及月降水量
*程序输入：
*程序输出：
*/
#include <stdio.h>
#define MONTHS 12
#define YEARS 5
int main()
{
//把数组初始化为2000到2004年的降水量数据
const float rain[YEARS][MONTHS] = {
{4.3,4.3,4.3,3.0,2.0,1.2,0.2,0.2,0.4,2.4,3.5,6.6},
{8.5,8.2,1.2,1.6,2.4,0.0,5.2,0.9,0.3,0.9,1.4,7.3},
{9.1,8.5,6.7,4.3,2.1,0.8,0.2,0.2,1.1,2.3,6.1,8.4},
{7.2,9.9,8.4,3.3,1.2,0.8,0.4,0.0,0.6,1.7,4.3,6.2},
{7.6,5.6,3.8,2.8,3.8,0.2,0.0,0.0,0.0,1.3,2.6,5.2}

};
int year,month;
float subot,total;

printf(" YEAR RAINFALL (inches) \n");
for(year=0,total=0;year<YEARS;year++)
{ //对于每一年，各月的总降水量
for (month=0,subot=0; month<MONTHS; month++)
subot+=rain[year][month];
printf("%5d %15.1f\n",2000+year,subot);
total+=subot;//所有年度降水量
}
printf("\nThe yearly average is %.1f inches.\n\n",total/YEARS);
printf("MONTHLY AVERAGES: \n\n");
printf(" Jan Feb Mar Apr May Jun Jul Aug Sep Oct ");
printf(" Nov Dec\n");

for(month=0;month<MONTHS;month++)
{
for(year=0,subot=0;year<YEARS;year++)
subot+=rain[year][month];
printf("%4.1f",subot/YEARS);

}
printf("\n");
return 0;

}

运行结果：