提取不重复的整数

题目描述

9876673

37689

#include <iostream>
using namespace std;

int getNum(int n){
int a = n;
int ret = 0;
int aa[10] = {0};
while(a != 0){
int temp = a % 10;
if(aa[temp] == 0){
ret = ret * 10 + temp;
aa[temp] = 1;
}
a = a / 10;
}
return ret;
}

int main(){
int n;
cin >> n;
int ret = getNum(n);
cout << ret <<endl;

return 0;

}