LeetCode 129:Sum Root to Leaf Numbers

Given a binary tree containing digits from

0-9

only, each root-to-leaf path could represent
a number.

An example is the root-to-leaf path

1->2->3

which represents the number

123

.

Find the total sum of all root-to-leaf numbers.

For example,

1
   / \
  2   3

The root-to-leaf path

1->2

represents the number

12

.

The root-to-leaf path

1->3

represents the number

13

.

Return the sum = 12 + 13 =

25

.

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class Solution {
public:
	int sumNumbers(TreeNode* root) {
		return dfs(root, 0);
	}

	int dfs(TreeNode* root, int sum){
		if (root == 0) return 0;
		if (root->left == NULL && root->right == NULL)
		{
			return sum * 10 + root->val;
		}

		return dfs(root->left, sum * 10 + root->val) + dfs(root->right, sum * 10 + root->val);
	}
};

#include<iostream>
#include<new>
#include<vector>
using namespace std;

//Definition for binary tree
struct TreeNode
{
	int val;
	TreeNode *left;
	TreeNode *right;
	TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};

class Solution {
public:
	int sumNumbers(TreeNode* root) {
		return dfs(root, 0);
	}

	int dfs(TreeNode* root, int sum){
		if (root == 0) return 0;
		if (root->left == NULL && root->right == NULL)
		{
			return sum * 10 + root->val;
		}

		return dfs(root->left, sum * 10 + root->val) + dfs(root->right, sum * 10 + root->val);
	}
};

	void createTree(TreeNode *&root)
	{
		int i;
		cin >> i;
		if (i != 0)
		{
			root = new TreeNode(i);
			if (root == NULL)
				return;
			createTree(root->left);
			createTree(root->right);
		}
	}

int main()
{
	Solution s;
	TreeNode *root;
	createTree(root);
	int path = s.sumNumbers(root);
    cout << path <<endl;
	system("pause");
	return 0;
}