mysql if对数据进行处理 having对数据进行查询 thinkphp中的exp支持更复杂的where查询

if ($this->_post('dosearch','isset')) { // 搜索
if ($s_name = $this->_post('s_name','isset')) {
$where['a.name'] = array('like','%'.$s_name.'%');
$this->assign('s_name',$s_name);
}

if ($s_category = $this->_post('s_category','isset')) {
$where['a.category_id'] = $s_category;
$this->assign('s_category',$s_category);
}

if ($s_status = $this->_post('s_status','isset')) {
$having ='status ='.$s_status; // 只支持字符串
$this->assign('s_status',$s_status);
}
}

// 获取商铺
$subQuery = M('User')->where(array('agent_id'=>$this->agent_id,'status'=>1))
->field('id')
->select(false);
$where['a.user_id'] = array('exp','in '.$subQuery);
$where['a.status'] = 1;
$list       = M()->table('sh_store a')
->join('sh_goods b on a.id = b.store_id')
->join('sh_category c on a.category_id = c.id')
->join('sh_mall_shop d on a.id = d.store_id and d.mall_id = '.$this->mall['id'])
->where($where)
->group('a.id')
->having($having)
->field('a.id as store_id,a.user_id,a.name as store_name,c.name as category_name,a.logo,count(b.id) as goods_count,if(d.id > 0,"1","2") as status')
->select();
$this->assign('list',$list);

SELECT a.id as store_id,a.user_id,a.name as store_name,c.name as category_name,a.logo,count(b.id) as goods_count,if(d.id > 0,"1","2") as status FROM sh_store a LEFT JOIN sh_goods b on a.id = b.store_id LEFT JOIN sh_category c on a.category_id = c.id LEFT JOIN sh_mall_shop d on a.id = d.store_id and d.mall_id = 9 WHERE ( a.category_id = '47' ) AND ( (a.user_id in ( SELECT `id` FROM `sh_user` WHERE ( `agent_id` = 13 ) AND ( `status` = 1 ) )) ) AND ( a.status = 1 ) GROUP BY a.id HAVING status =1