您的位置:首页 > 大数据 > 人工智能

Leetcode: Contains Duplicate II

2015-12-17 07:44 495 查看
Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k.


Better idea is to maintain a hashset that contains at most k numbers

public class Solution {
public boolean containsNearbyDuplicate(int[] nums, int k) {
Set<Integer> set = new HashSet<Integer>();
for(int i = 0; i < nums.length; i++){
if(set.contains(nums[i])) return true;
set.add(nums[i]);
if(set.size()>k) set.remove(nums[i-k]);
}
return false;
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: