1031. Hello World for U (20)【字符串处理】——PAT (Advanced Level) Practise
2015-12-02 22:02
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题目信息
1031. Hello World for U (20)时间限制400 ms
内存限制65536 kB
代码长度限制16000 B
Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, “helloworld” can be printed as:
h d e l l r lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible – that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.
Input Specification:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.
Output Specification:
For each test case, print the input string in the shape of U as specified in the description.
Sample Input:
helloworld!
Sample Output:
h ! e d l l lowor
解题思路
字符串操作AC代码
#include <stdio.h> #include <string.h> int main() { char s[100]; scanf("%s", s); int len = strlen(s); int tl = (len + 2) / 3 - 1; int sp = len - tl * 2 - 2; int i = 0; for (i = 0; i < tl; ++i){ putchar(s[i]); int t = sp; while (t-- > 0) putchar(' '); putchar(s[len - 1 - i]); putchar('\n'); } for (;i < len - tl; ++i) putchar(s[i]); putchar('\n'); return 0; }
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