您的位置:首页 > 其它

hdu 4666 Hyperspace(线段树)

2015-11-06 21:41 267 查看
题目链接:hdu 4666 Hyperspace

解题思路

线段树单点修改,区间查询。做2k维护ans数组即可。

代码

#include <cstdio>
#include <cstring>
#include <algorithm>

using namespace std;
#define lson(x) ((x)<<1)
#define rson(x) (((x)<<1)|1)
const int maxn = 60005;
const int inf = 0x3f3f3f3f;

int lc[maxn<<2], rc[maxn<<2], mi[maxn<<2], mx[maxn<<2];

void pushup(int u) {
mi[u] = min(mi[lson(u)], mi[rson(u)]);
mx[u] = max(mx[lson(u)], mx[rson(u)]);
}

void build (int u, int l, int r) {
lc[u] = l, rc[u] = r;
mi[u] = inf, mx[u] = -inf;

if (l == r) return;

int mid = (l + r) >> 1;
build(lson(u), l, mid);
build(rson(u), mid+1, r);
pushup(u);
}

void modify(int u, int x, int v) {
if (lc[u] == rc[u]) {
mi[u] = mx[u] = v;
return ;
}

int mid = (lc[u] + rc[u]) >> 1;
if (x <= mid) modify(lson(u), x, v);
else modify(rson(u), x, v);
pushup(u);
}

void clear(int u, int x) {
if (lc[u] == rc[u]) {
mi[u] = inf;
mx[u] = -inf;
return ;
}

int mid = (lc[u] + rc[u]) >> 1;
if (x <= mid) clear(lson(u), x);
else clear(rson(u), x);
pushup(u);
}

int N, K, ans[maxn];
int op[maxn], id[maxn], P[maxn][5];

void init () {
for (int i = 1; i <= N; i++) {
scanf("%d", &op[i]);
if (op[i]) scanf("%d", &id[i]);
else {
for (int j = 0; j < K; j++)
scanf("%d", &P[i][j]);
}
}
memset(ans, 0, sizeof(ans));
}

int get(int* x, int s) {
int ret = 0;
for (int i = 0; i < K; i++) {
if (s&(1<<i)) ret += x[i];
else ret -= x[i];
}
return ret;
}

int main () {
while (scanf("%d%d", &N, &K) == 2) {
init();
for (int i = 0; i < (1<<K); i++) {
build(1, 1, N);
for (int j = 1; j <= N; j++) {
if (op[j]) clear(1, id[j]);
else {
int tmp = get(P[j], i);
modify(1, j, tmp);
}
ans[j] = max(ans[j], mx[1] - mi[1]);
}
}
for (int i = 1; i <= N; i++)
printf("%d\n", ans[i]);
}
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: