<LeetCode><Easy> 171 Excel Sheet Column Number
2015-10-16 13:34
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Related to question Excel Sheet Column Title
Given a column title as appear in an Excel sheet, return its corresponding column number.
For example:
#Python2 76ms
class Solution(object):
def titleToNumber(self, s):
"""
:type s: str
:rtype: int
"""
s2n=lambda x:ord(x)-64
total=0
length=len(s)
for i in range(length):
total+=pow(26,length-i-1)*s2n(s[i])
return total
#Python2 72ms
class Solution(object):
def titleToNumber(self, s):
"""
:type s: str
:rtype: int
"""
s2n=lambda x:ord(x)-64
length=len(s)
return sum(pow(26,length-i-1)*s2n(s[i]) for i in range(length))
#Python2 68ms
class Solution(object):
def titleToNumber(self, s):
"""
:type s: str
:rtype: int
"""
s2n=lambda x:ord(x)-64
return sum(pow(26,s.__len__()-i-1)*s2n(s[i]) for i in range(s.__len__()))#Python 84ms
class Solution(object):
def titleToNumber(self, s):
"""
:type s: str
:rtype: int
"""
return sum(pow(26,s.__len__()-i-1)*(ord(s[i])-64) for i in range(s.__len__()))
Given a column title as appear in an Excel sheet, return its corresponding column number.
For example:
A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28
#Python2 76ms
class Solution(object):
def titleToNumber(self, s):
"""
:type s: str
:rtype: int
"""
s2n=lambda x:ord(x)-64
total=0
length=len(s)
for i in range(length):
total+=pow(26,length-i-1)*s2n(s[i])
return total
#Python2 72ms
class Solution(object):
def titleToNumber(self, s):
"""
:type s: str
:rtype: int
"""
s2n=lambda x:ord(x)-64
length=len(s)
return sum(pow(26,length-i-1)*s2n(s[i]) for i in range(length))
#Python2 68ms
class Solution(object):
def titleToNumber(self, s):
"""
:type s: str
:rtype: int
"""
s2n=lambda x:ord(x)-64
return sum(pow(26,s.__len__()-i-1)*s2n(s[i]) for i in range(s.__len__()))#Python 84ms
class Solution(object):
def titleToNumber(self, s):
"""
:type s: str
:rtype: int
"""
return sum(pow(26,s.__len__()-i-1)*(ord(s[i])-64) for i in range(s.__len__()))
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