<LeetCode><Easy> 6 ZigZag Conversion
2015-10-16 22:22
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The string
of rows like this: (you may want to display this pattern in a fixed font for better legibility)
And then read line by line:
Write the code that will take a string and make this conversion given a number of rows:
return
#Python2 156ms
"PAYPALISHIRING"is written in a zigzag pattern on a given number
of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line:
"PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)should
return
"PAHNAPLSIIGYIR".
#Python2 156ms
class Solution(object): def convert(self, s, numRows): """ :type s: str :type numRows: int :rtype: str """ if numRows<2: return s numRows2=2*numRows-2 dictRows={i:[] for i in range(numRows)} for i in range(len(s)): location=i%numRows2 if location>=numRows: location=numRows2-location dictRows[location].append(s[i]) rString="" for i in range(numRows): rString+="".join(dictRows[i]) return rString
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