您的位置:首页 > 其它

Number of Islands - leetcode

2015-10-03 14:06 302 查看
原题链接

题目:

Given a 2d grid map of '1's (land) and '0's (water), count the number of islands.
An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically.
You may assume all four edges of the grid are all surrounded by water.

Example 1:

11110
11010
11000
00000
Answer: 1

Example 2:

11000
11000
00100
00011
Answer: 3


思路:

把该矩阵变成一个图, 相当于求非连通子图的个数. 可以利用dfs/bfs来求解.
(如果一个图是全连通图, 那么dfs/bfs可一次遍历完该图)


code

class Solution {
public:
bool check(int m, int n, int x, int y) {
return x >= 0 && x < m && y >= 0 && y < n;
}

void dfs(vector<vector<char>>& grid, int m, int n, int x, int y) {
if(!check(m, n, x, y)) return;
if(grid[x][y] != '1') return;
// set statue: visited
grid[x][y] = 'v';
dfs(grid, m, n, x - 1, y);
dfs(grid, m, n, x + 1, y);
dfs(grid, m, n, x, y - 1);
dfs(grid, m, n, x, y + 1);
}

int numIslands(vector<vector<char>>& grid) {
if(grid.size() == 0) return 0;

int m = grid.size();
int n = grid[0].size();

int cnt = 0;
for(int i = 0; i < m; i++) {
for(int j = 0; j < n; j++) {
// if grid[i][j] has been not visited and is equal to '1',
// then dfs
if(grid[i][j] == '1') {
dfs(grid, m, n, i, j);
cnt++;
}
}
}

return cnt;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  leetcode dfs bfs