HDU 2602：Bone Collector【01背包】

Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 40266    Accepted Submission(s): 16731


[align=left]Problem Description[/align]
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …

The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the
maximum of the total value the bone collector can get ?



 

[align=left]Input[/align]
The first line contain a integer T , the number of cases.

Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third
line contain N integers representing the volume of each bone.
 

[align=left]Output[/align]
One integer per line representing the maximum of the total value (this number will be less than 231).
 

[align=left]Sample Input[/align]

1
5 10
1 2 3 4 5
5 4 3 2 1

 

[align=left]Sample Output[/align]

14

 
AC-code:

#include<cstdio>
#include<cstring>
#define max(a,b) a>b?a:b
int f[1005],c[1005],val[1005];
int main()
{
int t,n,v,i,j;
scanf("%d",&t);
while(t--)
{
memset(f,0,sizeof(f));
scanf("%d%d",&n,&v);
for(i=0;i<n;i++)
scanf("%d",&val[i]);
for(i=0;i<n;i++)
scanf("%d",&c[i]);
for(i=0;i<n;i++)
for(j=v;j>=c[i];j--)
f[j]=max(f[j],f[j-c[i]]+val[i]);
printf("%d\n",f[v]);
}
return 0;
}