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奇怪++操作

2015-07-18 08:03 435 查看
#include <stdio.h>

int main(void)
{
int j, i = 3;

printf("j = %d\n", j = (++i) + (++i) + (++i));

i = 3;
printf("j = %d\n", j = (i++) + (i++) + (i++));
i = 3;
printf("j = %d\n", j = (++i) + (i++) + (++i));

return 0;
}

/*
结果:
 * j = 16
* j = 9
* j = 13
* */


#include <stdio.h>

#define SQUARE(x) ((x)*(x))
int main(void)
{
int a = 5;
int b, c;

b = SQUARE(a++);
a = 5;
c = SQUARE(++a);

printf("b: %d, c: %d\n", b, c);

a = 5;
b = (a++)*(a++);
a = 5;
c = (++a)*(++a);

printf("b: %d, c: %d\n", b, c);

a = 5;
b = (a++)*(a++)*(a++);
a = 5;
c = (++a)*(++a)*(++a);

printf("b: %d, c: %d\n", b, c);

a = 5;
b = (a++)*(a++)*(++a);
a = 5;
c = (++a)*(a++)*(++a);
// 6*6*7 ?

?

?
a = 5;
c = (++a)*(a++);
// 6*6 ??

?

printf("b: %d, c: %d\n", b, c);

return 0;
}


运行结果:

b: 25, c: 49

b: 25, c: 49

b: 125, c: 392

b: 150, c: 36

++ 什么是法律表达式求值?

反编译它?
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