lintcode:Continuous Subarray Sum

Given an integer array, find a continuous subarray where the sum of numbers is the biggest. Your code should return the index of the first number and the index of the last number. (If their are duplicate answer, return anyone)

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Example

Give

[-3, 1, 3, -3, 4]

,
return

[1,4]

.

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class Solution {
public:
/**
* @param A an integer array
* @return  A list of integers includes the index of
*          the first number and the index of the last number
*/
vector<int> continuousSubarraySum(vector<int>& A) {
// Write your code here
vector<int> res;

if (A.size() == 0)
return res;

int curLeft  = 0;

int maxLeft  = curLeft;
int maxRight = 0;

int curSum = 0;
int maxSum = INT_MIN;

for (int i=0; i<A.size(); i++)
{
curSum += A[i];

if (curSum > maxSum)
{
maxLeft  = curLeft;
maxRight = i;
maxSum = curSum;
}

if (curSum < 0)
{
if (i+1 <= A.size()-1)
{
curSum = 0;
curLeft  = i+1;
}
}
}

res.push_back(maxLeft);
res.push_back(maxRight);

return res;
}
};