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Works Applications 面试题 2012

2015-06-03 17:06 411 查看
两个正整数M和N,M <= N,令0 < a < M,M <= b <= N,分别输出以a为分子b为分母的可约和不可约分数

#include <iostream>
#include <vector>
using namespace std;

int gcd(int m, int n)
{
    if (n == 0)
    {
        return m;
    }
    else
    {
        return gcd(n, m % n);
    }
}
int main()
{  
    int m, n;
    vector<string> canReduce, cannotReduce;
    while (cin >> m >> n)
    {
        if (m >= n)
        {
            break;
        }
        for (int i = 1; i < m; i++)
        {
            for (int j = m; j <= n; j++)
            {
                char str[10];      
                sprintf(str, "%d/%d", i, j);
                if (gcd(i, j) == 1)
                {                   
                    cannotReduce.push_back(str);
                }
                else
                {
                    canReduce.push_back(str);
                }
            }
        }
        for (int i = 0; i < canReduce.size(); i++)
        {
            cout << canReduce.at(i).c_str() << " ";
        }
        cout << endl;
        for (int i = 0; i < cannotReduce.size(); i++)
        {
            cout << cannotReduce.at(i).c_str() << " ";
        }
        cout << endl;
    }
    return 0;
}
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