您的位置:首页 > 其它

Leetcode_27 Remove Element

2015-05-31 11:50 288 查看
Question:

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

#include<stdio.h>
int removeElement(int *nums,int numsSize,int val)
{
	int count=0;
	int i;
	for(i=0;i<numsSize;i++)
	{
		if(*(nums+i)!=val)
		{
			*(nums+i-count)=*(nums+i);
		}
		else
		{
			count++;
		}
	}
	return (numsSize-count);
}
int main(void)
{
	int a[]={1,2,3,4,1,2,3,6};
	int t=removeElement(a,8,1);
	int i;
	printf("length %d\n",t);
	for(i=0;i<t;i++)
	{
		printf("%d",a[i]);
	}
}


                                            
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: