ACM-I'll play a trick on you

描述 Please look the picture carefully. Then I'll give you two integers and your task is output the third one.

Please never doubt the picture.



输入The first line is a number T(1<=T<=30), represents the number of case. The next T blocks follow each indicates a case.

Each case contains two integers A,B (1<=B<=A<=10^100)输出For each case, output the number of case and the third integer.样例输入

3
99 72
45 27
39 18

样例输出

27
18
21

代码：

01.

#include<iostream>

02.

#include<string>

03.

using

namespace

std;

04.

int

main()

05.

{

06.

int

t;

07.

cin>>t;

08.

while

(t--)

09.

{

10.

string a,b;

11.

int

i,sum=0;

12.

cin>>a>>b;

13.

for

(i =0;i <a.length();i++)

14.

sum += a[i] -

'0'

;

15.

for

(i = 0;i < b.length();i++)

16.

sum += b[i] -

'0'

;

17.

cout<<sum<<endl;

18.

}

19.

return

0;

20.

}