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HDOJ 1257 最少拦截系统

2015-05-11 22:53 281 查看
题意:一个导弹拦截系统拦截导弹的高度必须不低于前一次的高度,求拦截所有的导弹需要多少套拦截系统

链接:http://acm.hdu.edu.cn/showproblem.php?pid=1257

思路:求包含所有数的LIS的最少个数,通过数组维护每个LIS的最大值判断

注意点:无

以下为AC代码:

Run IDSubmit TimeJudge StatusPro.IDExe.TimeExe.MemoryCode Len.LanguageAuthor
113540592014-08-07 12:51:02Accepted125746MS376K958 BG++luminous11
#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <iostream>
#include <cstring>
#include <cstdio>
#include <string>
#include <vector>
#include <deque>
#include <list>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <cmath>
#include <ctime>
#include <cctype>
#include <climits>
#include <iomanip>
#include <cstdlib>
#include <algorithm>
//#include <unordered_map>
//#include <unordered_set>
#define ll long long
#define ull unsigned long long
#define all(x) (x).begin(), (x).end()
#define clr(a, v) memset( a , v , sizeof(a) )
#define pb push_back
#define RDI(a) scanf ( "%d", &a )
#define RDII(a, b) scanf ( "%d%d", &a, &b )
#define RDIII(a, b, c) scanf ( "%d%d%d", &a, &b, &c )
#define RS(s) scanf ( "%s", s )
#define PI(a) printf ( "%d", a )
#define PIL(a) printf ( "%d\n", a )
#define PII(a,b) printf ( "%d %d", a, b )
#define PIIL(a,b) printf ( "%d %d\n", a, b )
#define PIII(a,b,c) printf ( "%d %d %d", a, b, c )
#define PIIIL(a,b,c) printf ( "%d %d %d\n", a, b, c )
#define PL() printf ( "\n" )
#define PSL(s) printf ( "%s\n", s )
#define rep(i,m,n) for ( int i = m; i <  n; i ++ )
#define REP(i,m,n) for ( int i = m; i <= n; i ++ )
#define dep(i,m,n) for ( int i = m; i >  n; i -- )
#define DEP(i,m,n) for ( int i = m; i >= n; i -- )
#define repi(i,m,n,k) for ( int i = m; i <  n; i += k )
#define REPI(i,m,n,k) for ( int i = m; i <= n; i += k )
#define depi(i,m,n,k) for ( int i = m; i >  n; i += k )
#define DEPI(i,m,n,k) for ( int i = m; i >= n; i -= k )
#define READ(f) freopen(f, "r", stdin)
#define WRITE(f) freopen(f, "w", stdout)
using namespace std;
const double pi = acos(-1);
template <class T>
inline bool RD ( T &ret )
{
char c;
int sgn;
if ( c = getchar(), c ==EOF )return 0; //EOF
while ( c != '-' && ( c < '0' || c > '9' ) ) c = getchar();
sgn = ( c == '-' ) ? -1 : 1;
ret = ( c == '-' ) ? 0 : ( c - '0' );
while ( c = getchar() , c >= '0' && c <= '9' ) ret = ret * 10 + ( c - '0' );
ret *= sgn;
return 1;
}
inline void PD ( int x )
{
if ( x > 9 ) PD ( x / 10 );
putchar ( x % 10 + '0' );
}
const double eps = 1e-10;
const int dir[4][2] = { 1,0, -1,0, 0,1, 0,-1 };
struct node{
int x, y, cnt;
node(){}
node( int _x, int _y ) : x(_x), y(_y) {}
node( int _x, int _y, int _cnt ) : x(_x), y(_y), cnt(_cnt) {}
};
int num[100005];
int main()
{
int n;
while ( RDI ( n ) != EOF ){
int k;
int cnt = 0;
int m = 0;
rep ( i, 0, n ){
RDI ( k );
int j = 0;
for ( j = 0; j < m; j ++ ){
if ( num[j] > k ){
num[j] = k;
break;
}
}
if ( j == m ){
num[m++] = k;
cnt ++;
}
}
PIL ( m );
}
return 0;
}
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