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哈工大 数据库实验2-使用高级语言操作MySQL数据库

2015-04-25 17:42 726 查看
1.实验目的

学会使用高级语言访问MySQL数据库,并进行查询。

2.实验环境

Windows XP操作系统、MySQL关系数据库管理系统、MinGW编译器或Microsoft Visual C++编译器。

本次实验主要利用C语言访问MySQL数据库,也可以使用J***A,PHP等其他语言。



3.实验内容

3.1实验任务

在上次上机实验课建立的COMPANY数据库上,用C语言编写程序,完成如下查询,程序的命令行参数为:

company_query –q <Number> -p [Parameters]

其中,Number代表待执行查询的序号,Parameters为第Number号查询需要的参数列表。

待执行的9个查询为如下:

1:参加了项目编号为%PNO%的项目的员工号,其中%PNO%为C语言编写的程序的输入参数;

SELECT ESSN

from employee natural join works_on

where pno='P1'





2:参加了项目名为%PNAME%的员工名字,其中%PNAME%为C语言编写的程序的输入参数;

SELECT ename

from employee ,works_on, project

where employee.ESSN=works_on.ESSN and works_on.PNO=project.pno and PNAME ='SQL Project'











3:在%DNAME%工作的所有工作人员的名字和地址,其中%DNAME%为C语言编写的程序的输入参数;

SELECT ename,ADDRESS

from employee NATURAL join department

where DNAME='研发部'



4:在%DNAME%工作且工资低于%SALARY%元的员工名字和地址,其中%DNAME%和%SALARY%为C语言编写的程序的输入参数;



SELECT ename,ADDRESS

from employee NATURAL join department

where DNAME='研发部' and SALARY<3000

5:没有参加项目编号为%PNO%的项目的员工姓名,其中%PNO%为C语言编写的程序的输入参数;

SELECT DISTINCT ename

from employee

where ename not in (

SELECT DISTINCt ename

from employee NATURAL join works_on

where pno="P1"

)

6:由%ENAME%领导的工作人员的姓名和所在部门的名字,,其中%ENAME%为C语言编写的程序的输入参数;

SELECT ename,dname

from employee natural join department

where SUPERSSN=(

select eSSN

from employee

where ename='张红'

)

7:至少参加了项目编号为%PNO1%和%PNO2%的项目的员工号,其中%PNO1%和%PNO2%为C语言编写的程序的输入参数;

SELECT essn

from employee natural join works_on

where pno='P1' and essn in (

select essn

from employee natural join works_on

where pno ='P2'

)

8:员工平均工资低于%SALARY%元的部门名称,其中%SALARY%为C语言编写的程序的输入参数;

SELECT dNAME

from employee natural join department

GROUP BY dno

H***ING avg(SALARY)<3400

9:至少参与了%N%个项目且工作总时间不超过%HOURS%小时的员工名字,其中%N%和%SALARY%为C语言编写的程序的输入参数;

SELECT eNAME

from employee natural join works_on

GROUP BY eNAME

H***ING count(pno)> 2 and sum(HOURS)>=8

注意:

(1)在上课之前需准备上节实验所需要用到的COMPANY数据库.

(2)每人抽查三个查询,根据抽查情况给分

<?php

$command = "company_query –q 1 -p SQL Project";

/*

* $cmd = $_GET ["c"];

* $pmt1 = $_GET ["p1"];

* $pmt2 = $_GET ["p2"];

*/

$pattern="/[1-9]/";

preg_match($pattern, $command,$result);

$cmd=$result[0];

$pattern="/-p .*/";

/*

preg_match($pattern, $command,$result);

$pmt=substr($result[0],3);

$pmt=explode(" ", $pmt);

$pmt1=$pmt[0];

$pmt2=$pmt[1];

print_r($pmt);

*/

$cmd = 5;

$pmt1 = 'P1';

$pmt2 = 'P2';

$res = "";

// echo $cmd . $pmt1 . $pmt2 . "-----------";

switch ($cmd) {

case 1 :

// 1:参加了项目编号为%PNO%的项目的员工号,其中%PNO%为C语言编写的程序的输入参数;

$sql = "SELECT ESSN

from employee natural join works_on

where pno='$pmt1'";

$res .= "ESSN</br>";

break;

case 2 :

// 2:参加了项目名为%PNAME%的员工名字,其中%PNAME%为C语言编写的程序的输入参数;

$sql = "

SELECT ename

from employee ,works_on, project

where employee.ESSN=works_on.ESSN and works_on.PNO= project.pno and PNAME ='$pmt1'";

$res .= "ENAME</br>";

break;

case 3 :

// 3:在%DNAME%工作的所有工作人员的名字和地址,其中%DNAME%为C语言编写的程序的输入参数;

$sql = "SELECT ename,ADDRESS

from employee NATURAL join department

where DNAME='$pmt1'";

$res .= "ename ADDRESS</br>";

break;

case 4 :

// 4:在%DNAME%工作且工资低于%SALARY%元的员工名字和地址,其中%DNAME%和%SALARY%为C语言编写的程序的输入参数;

$sql = "

SELECT ename,ADDRESS

from employee NATURAL join department

where DNAME='$pmt1' and SALARY<$pmt2";

$res .= "ename ADDRESS</br>";

break;

case 5 :

// 5:没有参加项目编号为%PNO%的项目的员工姓名,其中%PNO%为C语言编写的程序的输入参数;

$sql = "

SELECT DISTINCT ename

from employee

where ename not in (

SELECT DISTINCt ename

from employee NATURAL join works_on

where pno='$pmt1'

)";

$res .= "ename</br>";

break;

case 6 :

// 6:由%ENAME%领导的工作人员的姓名和所在部门的名字,,其中%ENAME%为C语言编写的程序的输入参数;

$sql = "

SELECT ename,dname

from employee natural join department

where SUPERSSN=(select eSSN

from employee

where ename='$pmt1'

)";

$res .= "ename,dname</br>";

break;

case 7 :

// 7:至少参加了项目编号为%PNO1%和%PNO2%的项目的员工号,其中%PNO1%和%PNO2%为C语言编写的程序的输入参数;

$sql = "

SELECT essn

from employee natural join works_on

where pno='$pmt1' and essn in (

select essn

from employee natural join works_on

where pno ='$pmt2'

)";

$res .= "ESSN</br>";

break;

case 8 :

// 8:员工平均工资低于%SALARY%元的部门名称,其中%SALARY%为C语言编写的程序的输入参数;

$sql = "

SELECT dNAME

from employee natural join department

GROUP BY dno

H***ING avg(SALARY)<$pmt1";

$res .= " dNAME</br>";

break;

case 9 :

// 9:至少参与了%N%个项目且工作总时间不超过%HOURS%小时的员工名字,其中%N%和%SALARY%为C语言编写的程序的输入参数;

$sql = "

SELECT eNAME

from employee natural join works_on

GROUP BY eNAME

H***ING count(pno)> $pmt1 and sum(HOURS)>=$pmt2";

$res .= "eNAME</br>";

break;

}

echo $sql . "</br>";

$servername = "localhost";

$username = "root";

$password = "root";

$dbname = "company";

// 创建连接

$conn = new mysqli ( $servername, $username, $password, $dbname );

// 检测连接

if ($conn->connect_error) {

die ( "Connection failed: " . $conn->connect_error );

}

// $sql = "SELECT * FROM employee";

$result = $conn->query ( $sql );

$num = mysqli_num_fields ( $result );

if ($result->num_rows > 0) {

// 输出每行数据

while ( $row = $result->fetch_row () ) {

for($i = 0; $i < $num; $i ++) {

$res .= $row [$i] . " ";

}

$res .= "</br>";

}

} else {

echo "0 results";

}

echo $res;

$conn->close ();

?>
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