[LeetCode][Database]Employees Earning More Than Their Managers

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

+—-+——-+——–+———–+

| Id | Name | Salary | ManagerId |

+—-+——-+——–+———–+

| 1 | Joe 　 | 70000 | 3 　 |

| 2 | Henry | 80000 | 4 　 |

| 3 | Sam 　| 60000 | NULL |

| 4 | Max　 | 90000 | NULL |

+—-+——-+——–+———–+

Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

+———-+

| Employee|

+———-+

| Joe 　　　|

+———-+

题目大意说每个职员有自己的Id和对应的经理的Id。

求所有工资大于自己经理的职员

刚刚上过数据库的课，所以这道用Ｍysql的话挺水的：

SELECT a.NAME FROM Employee a, Employee b WHERE a.ManagerId = b.Id AND a.Salary > b.Salary;