【leetcode SQL】Employees Earning More Than Their Managers
2015-02-01 21:20
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The
and there is also a column for the manager Id.
Given the
their managers. For the above table, Joe is the only employee who earns more than his manager.
解决方案如下:
# Write your MySQL query statement below
Select a.Name as Employee
from Employee a inner join Employee b on a.ManagerId=b.Id
where a.Salary>b.Salary开始对sql感兴趣了~
Employeetable holds all employees including their managers. Every employee has an Id,
and there is also a column for the manager Id.
+----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Max | 90000 | NULL | +----+-------+--------+-----------+
Given the
Employeetable, write a SQL query that finds out employees who earn more than
their managers. For the above table, Joe is the only employee who earns more than his manager.
+----------+ | Employee | +----------+ | Joe | +----------+
解决方案如下:
# Write your MySQL query statement below
Select a.Name as Employee
from Employee a inner join Employee b on a.ManagerId=b.Id
where a.Salary>b.Salary开始对sql感兴趣了~
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