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Python中时间的处理之——timedelta篇

2015-04-07 14:49 399 查看
#! /usr/bin/python

# coding=utf-8

from datetime import datetime,timedelta

"""

timedelta代表两个datetime之间的时间差

"""

now = datetime.now()

past = past = datetime(2010,11,12,13,14,15,16)

timespan = now - past

#这会得到一个负数

past - now

attrs = [

("days","日"),( 'seconds',"秒"),( 'microseconds',"毫秒")

#('min',"最小"),( 'max',"最大"),

]

for k,v in attrs:

"timespan.%s = %s #%s" % (k,getattr(timespan, k),v)

"""

总共相差的秒数

"""

timespan.total_seconds()

"""

实例化一个timespan

请注意它的参数顺序

timedelta([days[, seconds[, microseconds[, milliseconds[, minutes[, hours[, weeks]]]]]]])

"""

timespan = timedelta(days=1)

now - timespan #返回的是datetime型

now + timespan

timespan * 2 #还可以乘哦。代表二倍

timespan / 13

#增加一个月

from calendar import monthrange

now + timedelta(days=monthrange(start.year,start.month)[1])

转自:http://www.cnblogs.com/goodspeed/archive/2011/11/06/python_timedelta.html
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