leetcode 184,185 Department Top Three Salaries/HIGHEST Salaries

The

Employee

table holds all employees. Every employee has an Id, and there is also a column for the department Id.

+----+-------+--------+--------------+
| Id | Name  | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Henry | 80000  | 2            |
| 3  | Sam   | 60000  | 2            |
| 4  | Max   | 90000  | 1            |
| 5  | Janet | 69000  | 1            |
| 6  | Randy | 85000  | 1            |
+----+-------+--------+--------------+

The

Department

table holds all departments of the company.

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

Write a SQL query to find employees who earn the top three salaries in each of the department. For the above tables, your SQL query should return the following rows.

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| IT         | Randy    | 85000  |
| IT         | Joe      | 70000  |
| Sales      | Henry    | 80000  |
| Sales      | Sam      | 60000  |
+------------+----------+--------+

Department Highest Salary
Total Accepted: 546 Total Submissions: 2921My SubmissionsQuestion Solution The [code]Employee

table holds all employees. Every employee has an Id, a salary, and there is also a column for the department Id.+----+-------+--------+--------------+| Id | Name | Salary | DepartmentId |+----+-------+--------+--------------+| 1 | Joe | 70000 | 1 || 2 | Henry | 80000 | 2 || 3 | Sam | 60000 | 2 || 4 | Max | 90000 | 1 |+----+-------+--------+--------------+[/code]The

Department

table holds all departments of the company.

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

Write a SQL query to find employees who have the highest salary in each of the departments. For the above tables, Max has the highest salary in the IT department and Henry has the highest salary in the Sales department.

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| Sales      | Henry    | 80000  |
+------------+----------+--------+

这两道题目的解法有些类似，就是where的条件有所不同，都使用了inner join。。on与my sql 用户自定义两种方法，不同之处在于where语句的稍微不同，

一个是t.rank<=3 求出前三个最大值,一个是t.rank=1排名第一的值

解法

SELECT d.NAME AS Department, t.NAME AS Employee, Salary FROM (  SELECT    DepartmentId,            NAME,            Salary,             @rank := IF(@prevDeptId != DepartmentId, 1,                          IF(@prevSalary = Salary, @rank, @rank + 1) ) AS Rank,            @prevDeptId := DepartmentId AS prevDeptId,            @prevSalary := Salary AS prevSalary  FROM      Employee e, (SELECT @rank := 0, @prevDeptId := NULL, @prevSalary := NULL) r  ORDER BY  DepartmentId ASC, Salary DESC) t INNER JOIN Department d ON t.DepartmentId = d.IDWHERE t.rank <= 3

# Write your MySQL query statement belowSELECT d.NAME AS Department, t.NAME AS Employee, Salary FROM (  SELECT    DepartmentId,            NAME,            Salary,             @rank := IF(@prevDeptId != DepartmentId, 1,                          IF(@prevSalary = Salary, @rank, @rank + 1) ) AS Rank,            @prevDeptId := DepartmentId AS prevDeptId,            @prevSalary := Salary AS prevSalary  FROM      Employee e, (SELECT @rank := 0, @prevDeptId := NULL, @prevSalary := NULL) r  ORDER BY  DepartmentId ASC, Salary DESC) t INNER JOIN Department d ON t.DepartmentId = d.IDWHERE t.rank =1