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VIM--矩阵转置运算

2014-12-09 22:54 155 查看
 

#include<iostream>
#include<vector>
using namespace std;

void PrintMatrix(vector<vector<int> >& Matrix)
{
int n = Matrix.size();
for(int i = 0; i < n; ++i)
{
cout << "[" ;
for(int j = 0; j < n; ++j)
{
cout << Matrix[i][j] ;
}
cout << "]";
cout << '\n';
}
}

void TofArray(vector<vector<int> >& matrix)
{
const int n = matrix.size();

// 主对角线反转
for(int i = 0; i < n; ++i)
{
for(int j = 0; j < n-i; ++j)
swap(matrix[i][j], matrix[n-1-j][n-1-i]);
}
cout << "主对角线反转: " << '\n';
PrintMatrix(matrix);
cout << '\n';

// 水平中线反转
for(int i = 0; i < n/2; ++i)
{
for(int j = 0; j < n; ++j)
{
swap(matrix[i][j], matrix[n-1-i][j]);
}
}
cout << "水平中线反转: " << '\n';
PrintMatrix(matrix);
cout << '\n';

// 垂直中线反转
for(int i = 0; i < n; ++i)
{
for(int j = 0; j < n/2; ++j)
{
swap(matrix[i][j], matrix[i][n-1-j]);
}
}
cout << "垂直中线反转: " << '\n';
PrintMatrix(matrix);
cout << '\n';
}

int main(int argc, char* argv[])
{
vector<int> row1;
row1.push_back(1), row1.push_back(2), row1.push_back(3);

vector<int> row2;
row2.push_back(4), row2.push_back(5), row2.push_back(6);

vector<int> row3;
row3.push_back(7), row3.push_back(8), row3.push_back(9);

vector<vector<int> > Matrix(3);
Matrix[0] = row1;
Matrix[1] = row2;
Matrix[2] = row3;

cout << "Row matrix is: " << '\n';
PrintMatrix(Matrix);
cout << '\n';

TofArray(Matrix);
cout << "After T of Matrix is: " << '\n';
PrintMatrix(Matrix);
cout << '\n';
return 0;
}


 



 

 

 
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标签:  vim matrix