void*和类成员函数指针的相互转换

linux环境下，强地址转换会在O3的时候出问题

正确的代码如下，

#include <stdio.h>

#include <stdlib.h>

#include <new>

#include <string.h>

class class1

{

public:

class1()

{

b = 10;

}

int memfunc1(int a)

{

printf("memfunc1 this %p\n", this);

return a - b;

}

private:

int b;

};

template <typename F>

F fkvoidcastmemfunc(void * p)

{

return *(F*)p;

}

void* mymalloc(size_t size)

{

printf("mymalloc %d\n", size);

return malloc(size);

}

template <typename F>

void * fkmemfunccastvoid(F f)

{

void * p = mymalloc(sizeof(F));

new(p) F(f);

return p;

}

typedef int (class1::*func1)(int);

int main(int argc, const char *argv[])

{

class1 * p = new class1;

func1 f = &class1::memfunc1;

(p->*(f))(2);

printf("f %p %d\n", f, sizeof(func1));

void * pp = fkmemfunccastvoid(f);

printf("pp %p\n", pp);

func1 fff = fkvoidcastmemfunc<func1>(pp);

printf("fff %p\n", fff);

if (f == fff)

{

printf("f == fff\n");

}

else

{

printf("f %p != fff %p\n", f, fff);

}

(p->*(fff))(2);

return 0;

}