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PHP计算2点经纬度之间的距离代码

2014-10-12 18:19 447 查看
function getDistanceBetweenPointsNew($latitude1, $longitude1, $latitude2, $longitude2) {

$theta = $longitude1 - $longitude2;

$miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));

$miles = acos($miles);

$miles = rad2deg($miles);

$miles = $miles * 60 * 1.1515;

$feet = $miles * 5280;

$yards = $feet / 3;

$kilometers = $miles * 1.609344;

$meters = $kilometers * 1000;

return compact('miles','feet','yards','kilometers','meters');

}

$point1 = array('lat' => 40.770623, 'long' => -73.964367);

$point2 = array('lat' => 40.758224, 'long' => -73.917404);

$distance = getDistanceBetweenPointsNew($point1['lat'], $point1['long'], $point2['lat'], $point2['long']);

foreach ($distance as $unit => $value) {

echo $unit.': '.number_format($value,4).'<br />';

}

The example returns the following:

miles: 2.6025

feet: 13,741.4350

yards: 4,580.4783

kilometers: 4.1884

meters: 4,188.3894
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