python 时间处理

 在实际中遇到一个时间处理问题，需要将 Sep 06, 2014 19:30 （UTC 时间） 和 当前时间比较早晚，知道 此 2014-09-06 19:30 格式时间的运算。因此，在处理时，就想

先将sep 格式时间转化成 后面一个格式的时间样子，没有找到相关函数，于是自己简单的写了个程序，仅记于此，以备查询

代码如下：

 # -*- coding: utf-8 -*-
from datetime import date
from datetime import datetime
from datetime import timedelta

# # #如果是返回当前时间，可以简单的写成
# # time.localtime()
# # #这个返回UTC时间
# # time.gmtime()
# lt = time.localtime()
# tm = time.gmtime()
# ft = time.strftime('%Y-%m-%d %H-%M',lt)
# ft2 = time.strftime('%Y-%m-%d %H:%M',tm)
# print ft, ft2
# print '--------------------------------------------------------'
# now = datetime.datetime.now()
# now = now.replace(day = 1)
# print now
# print now.time()
#
# mytime = ['2014-09-06 20:19']
# #mytime2 = '2014-10-09 14:32'
# str = "".join(mytime)
# print str
# retime = datetime.strptime(str,'%Y-%m-%d %H:%M')
# print retime
# retime = retime +timedelta(hours = 8)
# print retime
#
# tdtime = datetime.now()
# print tdtime
# if retime <= tdtime - timedelta(days = 7):
# print "too early"
#
# #Sep 06, 2014 19:30

monthdic = {'Jan':'01', 'Feb':'02', 'Mar':'03', 'Apr':'04', 'May':'05', 'Jun':'06', 'Jul':'07', 'Aug':'08', 'Sep':'09', 'Oct':'10', 'Nov':'11', 'Dec':'12'}
def time_format(timestr):
timestr = timestr.replace(',','')
#print timestr
timelist = timestr.split()
#print timelist
mon = "".join(timelist[0])
#print mon
timelist[0] = monthdic[mon]
#print timelist
mytime = "".join(timelist[2])+'-'+"".join(timelist[0])+'-'+"".join(timelist[1])+' '+ "".join(timelist[3])
return mytime
if __name__ == '__main__':
timestr = 'Sep 06, 2014 19:30'
str = time_format(timestr)
print str
mytime = datetime.strptime(str,'%Y-%m-%d %H:%M')
print mytime
mytime = mytime +timedelta(hours = 8)
print mytime
tdtime = datetime.now()
print tdtime
if mytime <= tdtime - timedelta(days = 7):
print "too early"