地球坐标系 (WGS-84) 到火星坐标系 (GCJ-02)百度坐标系 (BD-09) 的转换算法 .

地球坐标系 (WGS-84) 到火星坐标系 (GCJ-02) 的转换算法

WGS-84 到 GCJ-02 的转换（即 GPS 加偏）算法是一个普通青年轻易无法接触到的“公开”的秘密。这个算法的代码在互联网上是公开的，详情请使用
Google 搜索 "wgtochina_lb" 。

整理后的算法代码请参考 https://on4wp7.codeplex.com/SourceControl/changeset/view/21483#353936 。知道了这个算法之后，就可以离线进行 Google 地图偏移校正，不必像之前那么麻烦。

至于 GCJ-02 到 WGS-84 的转换（即 GPS 纠偏），可以使用二分法。

[csharp]
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using System;

namespace Navi
{
class EvilTransform
{
const double pi = 3.14159265358979324;

//
// Krasovsky 1940
//
// a = 6378245.0, 1/f = 298.3

// b = a * (1 - f)

// ee = (a^2 - b^2) / a^2;

const double a = 6378245.0;
const double ee = 0.00669342162296594323;

//
// World Geodetic System ==> Mars Geodetic System

public static void transform(double wgLat, double wgLon, out double mgLat, out double mgLon)
{
if (outOfChina(wgLat, wgLon))
{
mgLat = wgLat;
mgLon = wgLon;
return;
}
double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);
double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);
double radLat = wgLat / 180.0 * pi;
double magic = Math.Sin(radLat);
magic = 1 - ee * magic * magic;
double sqrtMagic = Math.Sqrt(magic);
dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
mgLat = wgLat + dLat;
mgLon = wgLon + dLon;
}

static bool outOfChina(double lat, double lon)
{
if (lon < 72.004 || lon > 137.8347)
return true;
if (lat < 0.8293 || lat > 55.8271)
return true;
return false;
}

static double transformLat(double x, double y)
{
double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.Sqrt(Math.Abs(x));
ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
ret += (20.0 * Math.Sin(y * pi) + 40.0 * Math.Sin(y / 3.0 * pi)) * 2.0 / 3.0;
ret += (160.0 * Math.Sin(y / 12.0 * pi) + 320 * Math.Sin(y * pi / 30.0)) * 2.0 / 3.0;
return ret;
}

static double transformLon(double x, double y)
{
double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.Sqrt(Math.Abs(x));
ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
ret += (20.0 * Math.Sin(x * pi) + 40.0 * Math.Sin(x / 3.0 * pi)) * 2.0 / 3.0;
ret += (150.0 * Math.Sin(x / 12.0 * pi) + 300.0 * Math.Sin(x / 30.0 * pi)) * 2.0 / 3.0;
return ret;
}
}
}

using System;

namespace Navi
{
class EvilTransform
{
const double pi = 3.14159265358979324;

//
// Krasovsky 1940
//
// a = 6378245.0, 1/f = 298.3
// b = a * (1 - f)
// ee = (a^2 - b^2) / a^2;
const double a = 6378245.0;
const double ee = 0.00669342162296594323;

//
// World Geodetic System ==> Mars Geodetic System
public static void transform(double wgLat, double wgLon, out double mgLat, out double mgLon)
{
if (outOfChina(wgLat, wgLon))
{
mgLat = wgLat;
mgLon = wgLon;
return;
}
double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);
double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);
double radLat = wgLat / 180.0 * pi;
double magic = Math.Sin(radLat);
magic = 1 - ee * magic * magic;
double sqrtMagic = Math.Sqrt(magic);
dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
mgLat = wgLat + dLat;
mgLon = wgLon + dLon;
}

static bool outOfChina(double lat, double lon)
{
if (lon < 72.004 || lon > 137.8347)
return true;
if (lat < 0.8293 || lat > 55.8271)
return true;
return false;
}

static double transformLat(double x, double y)
{
double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.Sqrt(Math.Abs(x));
ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
ret += (20.0 * Math.Sin(y * pi) + 40.0 * Math.Sin(y / 3.0 * pi)) * 2.0 / 3.0;
ret += (160.0 * Math.Sin(y / 12.0 * pi) + 320 * Math.Sin(y * pi / 30.0)) * 2.0 / 3.0;
return ret;
}

static double transformLon(double x, double y)
{
double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.Sqrt(Math.Abs(x));
ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
ret += (20.0 * Math.Sin(x * pi) + 40.0 * Math.Sin(x / 3.0 * pi)) * 2.0 / 3.0;
ret += (150.0 * Math.Sin(x / 12.0 * pi) + 300.0 * Math.Sin(x / 30.0 * pi)) * 2.0 / 3.0;
return ret;
}
}
}

参考:
http://blog.csdn.net/coolypf/article/details/8686588 http://blog.csdn.net/giswens/article/details/8775283 https://on4wp7.codeplex.com/SourceControl/changeset/view/21483#353936
火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法

关于 GCJ-02 和 BD-09 ，请参考 http://developer.baidu.com/map/question.htm#qa0043 。

算法代码如下，其中

bd_encrypt

将 GCJ-02 坐标转换成 BD-09 坐标，

bd_decrypt

反之。

[cpp]
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#include <math.h>

const double x_pi = 3.14159265358979324 * 3000.0 / 180.0;

void bd_encrypt(double gg_lat, double gg_lon, double &bd_lat, double &bd_lon)
{
double x = gg_lon, y = gg_lat;
double z = sqrt(x * x + y * y) + 0.00002 * sin(y * x_pi);
double theta = atan2(y, x) + 0.000003 * cos(x * x_pi);
bd_lon = z * cos(theta) + 0.0065;
bd_lat = z * sin(theta) + 0.006;
}

void bd_decrypt(double bd_lat, double bd_lon, double &gg_lat, double &gg_lon)
{
double x = bd_lon - 0.0065, y = bd_lat - 0.006;
double z = sqrt(x * x + y * y) - 0.00002 * sin(y * x_pi);
double theta = atan2(y, x) - 0.000003 * cos(x * x_pi);
gg_lon = z * cos(theta);
gg_lat = z * sin(theta);
}

#include <math.h>

const double x_pi = 3.14159265358979324 * 3000.0 / 180.0;

void bd_encrypt(double gg_lat, double gg_lon, double &bd_lat, double &bd_lon)
{
double x = gg_lon, y = gg_lat;
double z = sqrt(x * x + y * y) + 0.00002 * sin(y * x_pi);
double theta = atan2(y, x) + 0.000003 * cos(x * x_pi);
bd_lon = z * cos(theta) + 0.0065;
bd_lat = z * sin(theta) + 0.006;
}

void bd_decrypt(double bd_lat, double bd_lon, double &gg_lat, double &gg_lon)
{
double x = bd_lon - 0.0065, y = bd_lat - 0.006;
double z = sqrt(x * x + y * y) - 0.00002 * sin(y * x_pi);
double theta = atan2(y, x) - 0.000003 * cos(x * x_pi);
gg_lon = z * cos(theta);
gg_lat = z * sin(theta);
}

http://blog.csdn.net/giswens/article/details/8775275
其他参考
http://www.zuidaima.com/code/file/1665077235663872.htm?dir=/correct_lat_lon/src/com/hgq/correct/MapFix.java