您的位置:首页 > 编程语言 > PHP开发

Ajax请求php返回json对象数据中包含有数字索引和字符串索引,在for in循环中取出数据的顺序问题

2014-08-08 17:20 591 查看
//php中的数组数据格式
Array
(
[all] => Array
(
[title] => ALL
[room_promotion_id] => all
)

[best_available_rate] => Array
(
[title] => Best Available Rate
[room_promotion_id] => best_available_rate
)

[30] => Array
(
[room_promotion_id] => 30
[version] => 1
[date_from] => 2014-08-05
[date_to] => 2014-09-30
[night_no] => 1
[discount_stype] => 1
[discount_rate] => 10
[discount_night] => 0
[title] => Summer Discount - Premier Suite
[summary] => <p>
Bring your family along to relax in the Summer! Enjoy a 10% off whenever you book Premier Suite.</p>

[before_day] => 0
)

)


//json_encode()之后输出的数据,这也是ajax返回的json数据对象
{"all":{"title":"ALL","room_promotion_id":"all"},
"best_available_rate":{"title":"Best Available Rate","room_promotion_id":"best_available_rate"},
"30":{"room_promotion_id":"30","version":"1","date_from":"2014-08-05","date_to":"2014-09-30","night_no":"1","discount_stype":"1",
"discount_rate":"10","discount_night":"0","title":"Summer Discount - Premier Suite",
"summary":"<p>\r\n\tBring your family along to relax in the Summer! Enjoy a 10% off whenever you book Premier Suite.<\/p>\r\n","before_day":"0"}}


//javascript代码

function ajaxPrmotion(){
var check_in_hidden = $('#check_in_hidden').val();
var check_out_hidden = $('#check_out_hidden').val();
var adults_num = $('#adult').attr('selected','selected').val();
var child_num  = $('#child').attr('selected','selected').val();
var promotion_opt ='';
var url= "reservation.php?action_type=mobile_ajax&check_in="+check_in_hidden+"&check_out="+check_out_hidden+"&adult="+adults_num+"&child="+child_num+"&upd=1";

$.ajax({
url:url,
type : "get",
dataType : "json",
success: function(result) {
//$("select[name=promotion_id]").find("option").remove().end().append("<option value='0'>__($lang_text.best_rate)__</option>");
$("select[name=promotion_id]").find("option").remove();
var promotion_opt ='';
if (result!='' && result){
        /×
                使用for(var variablename in object){}循环出来的数据顺序与php中打印输出的数组中数据的顺序和json_encode()后的数据顺序是不同
                最先循环取到的索引为30的数据,然后是all和best_available_rate,不知道这个究竟是怎么一回事。
                因为在php中的数组中的顺序已经固定好了,json_encode()出来的数据也是和php数组中的顺序相同,但是为何在javascript中使用for in出来的数据
                顺序反而不相同呢?只有两个原因: 1.jquery中对传输的json格式数据进行了排序吗?2.要么就是在for in发生的问题了
               ×/

for(var promotion in result){
promotion_opt += '<option value="' +result[promotion]["room_promotion_id"]+'">'+ result[promotion]["title"]+'</option>';
}
}
$("select[name=promotion_id]").append(promotion_opt);
}
});
}


所以,我自己写一段javascript代码来进行测试,发现问题的原因是在javascript的for in上面.

测试代码如下:

<script type="text/javascript">

var json_data = {"all":{"title":"all","room_promotion_id":"all"},
"best_room_rate":    {"title":"best_room_rate","roompromotion_id":"best_room_rate"},
"30":{"title":"Summer Room rate" , "room_promotion_id":"30"}
};

for(var promotion in json_data){
alert(promotion);// 30->all->best_room_rate
}
</script>


针对上面的代码,我将"30"这个数字修改为"summer rate",代码如下:

<script type="text/javascript">
var json_data = {"all":{"title":"all","room_promotion_id":"all"},
"best_room_rate":{"title":"best_room_rate","roompromotion_id":"best_room_rate"},
"summer rate":{"title":"Summer Room rate" , "room_promotion_id":"30"}
};

for(var promotion in json_data){
alert(promotion);
//这次循环输出的结果完全就是按照上面定义的json_data数据中顺序
}
</script>


从上面的代码比较,我得出下面的结论,也许我的结论不一定是完全正确和合乎科学的。

结论:当json格式数据中既有包含有数字索引和文字索引时,那么在for in循环中首先取出来必定是数字索引的数据,然后就是按顺序取出文字索引的数据。
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: