“黑马程序员” 计算1`100之间7的倍数的个数。并打印

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//试题:1`100之间 7的倍数的个数。并打印
package 练习;

public class test2 {

public static void main(String[] args)

{

int y = 0 ;

for(int x = 1;x<=100;x++)

{

if (x%7==0)

{

y++;

System.out.println(x);

x++;

}else

x++;

}

System.out.println("1`100之间 7的倍数的个数有"+y);

}

}

---------------------- <a href="http://www.itheima.com"target="blank">ASP.Net+Unity开发</a>、<a href="http://www.itheima.com"target="blank">.Net培训</a>、期待与您交流！
----------------------