python实现统计汉字／英文单词数的正则表达式

思路

•使用正则式 "(?x) (?: [w-]+ | [x80-xff]{3} )"获得utf-8文档中的英文单词和汉字的列表。

•使用dictionary来记录每个单词／汉字出现的频率，如果出现过则＋1，如果没出现则置1。

•将dictionary按照value排序，输出。

源码

代码如下:

#!/usr/bin/python

# -*- coding: utf-8 -*-

#

#author: rex

#blog: http://iregex.org
#filename counter.py

#created: Mon Sep 20 21:00:52 2010

#desc: convert .py file to html with VIM.

import sys

import re

from operator import itemgetter

def readfile(f):

with file(f,"r") as pFile:

return pFile.read()

def divide(c, regex):

#the regex below is only valid for utf8 coding

return regex.findall(c)

def update_dict(di,li):

for i in li:

if di.has_key(i):

di[i]+=1

else:

di[i]=1

return di

def main():

#receive files from bash

files=sys.argv[1:]

#regex compile only once

regex=re.compile("(?x) (?: [w-]+ | [x80-xff]{3} )")

dict={}

#get all words from files

for f in files:

words=divide(readfile(f), regex)

dict=update_dict(dict, words)

#sort dictionary by value

#dict is now a list.

dict=sorted(dict.items(), key=itemgetter(1), reverse=True)

#output to standard-output

for i in dict:

print i[0&#…………………………………………………………………………
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