Leetcode 贪心 Best Time to Buy and Sell StockII
2014-05-12 20:35
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Total Accepted: 13030 Total
Submissions: 36467
Say you have an array for which the ith element is the price of a given stock on day i.
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions
at the same time (ie, you must sell the stock before you buy again).
题意:给定一组数,表示某种股票每天的交易价格。求如何进行买卖,使收益最大。可以进行多次买卖。
思路:贪心
买,然后在跌之前卖掉,再买,再在跌之前卖掉,一直这样贪心下去
复杂度:时间O(n),空间O(1)
相关题目:
Best Time to Buy and Sell Stock
Best Time to Buy and Sell StockIII
class Solution {
public:
int maxProfit(vector<int> &prices) {
if (prices.size() < 2) return 0;
int sum = 0;
for(int i = 1; i < prices.size(); i++){
int diff = prices[i] - prices[i - 1];
sum += diff > 0 ? diff : 0;
}
return sum;
}
};
Best Time to Buy and Sell Stock II
Total Accepted: 13030 TotalSubmissions: 36467
Say you have an array for which the ith element is the price of a given stock on day i.
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions
at the same time (ie, you must sell the stock before you buy again).
题意:给定一组数,表示某种股票每天的交易价格。求如何进行买卖,使收益最大。可以进行多次买卖。
思路:贪心
买,然后在跌之前卖掉,再买,再在跌之前卖掉,一直这样贪心下去
复杂度:时间O(n),空间O(1)
相关题目:
Best Time to Buy and Sell Stock
Best Time to Buy and Sell StockIII
class Solution {
public:
int maxProfit(vector<int> &prices) {
if (prices.size() < 2) return 0;
int sum = 0;
for(int i = 1; i < prices.size(); i++){
int diff = prices[i] - prices[i - 1];
sum += diff > 0 ? diff : 0;
}
return sum;
}
};
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