USACO Section 1.5: Prime Palindromes
2014-04-15 11:33
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这题的关键点:
1.不能检查是否palindrome,否则会TLE
2.检查Prime上限一定为sqrt(x)。
1.不能检查是否palindrome,否则会TLE
2.检查Prime上限一定为sqrt(x)。
/* ID: leetcod3 PROG: pprime LANG: C++ */ #include <iostream> #include <fstream> #include <string> #include <map> #include <vector> #include <set> #include <algorithm> #include <queue> #include <cmath> #include <list> #include <cstring> #include <cstdlib> #include <limits> #include <stack> using namespace std; ofstream fout ("pprime.out"); ifstream fin ("pprime.in"); vector<int> S; bool prime(int x) { int root = (int)sqrt(x*1.0); for (int i = 2; i <= root; i++) { if (x % i == 0) return false; } return true; } void dfs(int x, int len) { if (len > 8) return; int factor = 1; if (prime(x)) S.push_back(x); for (int i = 0; i < len; ++i) factor *= 10; for (int i = 0; i < 10; ++i) { int tmp = factor * i; tmp += x; tmp *= 10; tmp += i; dfs(tmp, len+2); } } int main() { int a, b; fin >> a >> b; for (int i = 0; i < 10; i++) dfs(i, 1); S.push_back(11); sort(S.begin(), S.end()); for (int i = 0; i < S.size(); i++) { if (S[i] < a) continue; if (S[i] > b) break; fout << S[i] << endl; } /*for (set<int>::iterator it = S.begin(); it != S.end(); it++) { if (*it < a) continue; if (*it > b) break; fout << *it << endl; }*/ return 0; }
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