【C】制作简单的时钟减法程序

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define ARGC_NUM 3
#define MAX_STR_NUM 6
#define H_AND_M_NUM 3
#define DELIMS ":"
#define M_2_S 60
#define D_2_H 24*M_2_S
int findH_M(char*str, char*h, char*m)
{
char* pTmp=NULL;
int ulTmp=0;
pTmp=strtok(str, DELIMS);
ulTmp=strlen(pTmp);
if (ulTmp>=H_AND_M_NUM)
{
printf("Error arg: %s\n", str);
return -1;
}
memcpy(h, pTmp, ulTmp);

pTmp=strtok(NULL, DELIMS);
ulTmp=strlen(pTmp);
if (ulTmp>=H_AND_M_NUM)
{
printf("Error arg: %s\n", str);
return -1;
}
memcpy(m, pTmp, ulTmp);
return 0;
}

/* 只支持24小时以内的时钟减法 */
int main(int argc, char* argv[])
{
char strBegin[MAX_STR_NUM]="";
char strEnd[MAX_STR_NUM]="";
char BeginH[H_AND_M_NUM]="";
char BeginM[H_AND_M_NUM]="";
char EndH[H_AND_M_NUM]="";
char EndM[H_AND_M_NUM]="";
unsigned int ulBeginTimeM=0;
unsigned int ulEndTimeM=0;
int BeginLen=0;
int EndLen=0;
if (0 == strcmp("-h", argv[1]))
{
printf("Useage: calcTime BeginTime EndTime \n""e.g. calcTime 18:58 19:59\n");
return 0;
}

if (ARGC_NUM != argc)
{
printf("Error! argc=%d\n", argc);
return -1;
}
BeginLen=strlen(argv[1]);
EndLen=strlen(argv[2]);

if ((BeginLen>=MAX_STR_NUM) || (EndLen>=MAX_STR_NUM))
{
printf("Error len! argv[1]=%s, argv[2]=%s\n", argv[1], argv[2]);
return -1;
}

memcpy(strBegin, argv[1], BeginLen);
memcpy(strEnd, argv[2], EndLen);

if ((0 != findH_M(strBegin, BeginH, BeginM)) || (0 != findH_M(strEnd, EndH, EndM)))
{
return -1;
}
ulBeginTimeM=atoi(BeginH)*M_2_S+atoi(BeginM);
ulEndTimeM=atoi(EndH)*M_2_S+atoi(EndM);
ulEndTimeM=(ulEndTimeM>ulBeginTimeM)?(ulEndTimeM):(ulEndTimeM+D_2_H);
printf("Congratulations! End-Begin is %d:%d\n", (ulEndTimeM-ulBeginTimeM)/M_2_S,(ulEndTimeM-ulBeginTimeM)%M_2_S);
return 0;
}

使用方法：

X:\gcc>calcTime -h
Useage: calcTime BeginTime EndTime
e.g. calcTime 18:58 19:59

X:\gcc> calcTime 18:58 19:59
Congratulations! End-Begin is 1:1