MySQL基础面试题
2014-03-27 00:44
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create table `t1` ( `id` double , `name` varchar (300), `score` double ); insert into `t1` (`id`, `name`, `score`) values('1','n1','59'); insert into `t1` (`id`, `name`, `score`) values('2','n2','66'); insert into `t1` (`id`, `name`, `score`) values('3','n3','78'); insert into `t1` (`id`, `name`, `score`) values('4','n1','48'); insert into `t1` (`id`, `name`, `score`) values('5','n3','85'); insert into `t1` (`id`, `name`, `score`) values('6','n5','51'); insert into `t1` (`id`, `name`, `score`) values('7','n4','98'); insert into `t1` (`id`, `name`, `score`) values('8','n5','53'); insert into `t1` (`id`, `name`, `score`) values('9','n2','67'); insert into `t1` (`id`, `name`, `score`) values('10','n4','88'); 1. 单分数最高的人和单分数最低的人。 mysql> select name,max(score) from t1; 2. 两门分数加起来的第2至5名。 mysql> select name,sum(score) from t1 group by name order by sum(score) desc limit 1,4; SELECT a.name,SUM(a.score) FROM t1 as a GROUP BY a.name ORDER BY a.score DESC LIMIT 1,4;+------+------------+ | name | sum(score) | +------+------------+ | n3 | 163 | | n2 | 133 | | n1 | 107 | | n5 | 104 | +------+------------+ 3. 两门总分数在150分以下的人。 select name sum(score) from t1 group by name having sum(score) < 150; SELECT a.name,SUM(a.score) FROM t1 as a GROUP BY a.name HAVING SUM(a.score)<150 ORDER BY SUM(a.score) DESC; 4. 两门平均分数介于60和80的人。 select name,avg(score) from t1 group by name having avg(score) between 60 and 80; select name,avg(score) from t1 group by name having ave(score) >60 and avg(score) <80; SELECT a.name,AVG(a.score) FROM t1 as a GROUP BY a.name HAVING AVG(a.score)BETWEEN 60 AND 80 ORDER BY AVG(a.score) DESC; 5. 总分大于150分,平均分小于90分的人数。 mysql> select name,sum(score),avg(score) from t1 group by name having sum(score)>150 and avg(score)<90; SELECT a.name,AVG(a.score),SUM(a.score) FROM t1 as a GROUP BY a.name HAVING AVG(a.score)<90 AND SUM(a.score)>150 ORDER BY AVG(a.score) DESC; +------+------------+------------+ | name | sum(score) | avg(score) | +------+------------+------------+ | n3 | 163 | 81.5 | +------+------------+------------+ 1 row in set (0.00 sec) 6. 总分大于150分,平均分小于90分的人数有几个。 select count(distinct name) from t1 group by name having sum(score) > 150 and avg(score) < 90; SELECT a.name,AVG(a.score),SUM(a.score),COUNT(distinct a.name) FROM t1 as a GROUP BY a.name HAVING AVG(a.score)<90 AND SUM(a.score)>150 ORDER BY AVG(a.score) DESC;
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