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如何在python3.3用 map filter reduce

2013-12-12 16:25 429 查看
在3.3里,如果直接使用map(), filter(), reduce(), 会出现

>>>def f(x): return x % 2 != 0 and x % 3 != 0

>>>filter(f, range(2, 25)) <</span>filter object at 0x0000000002C14908>

>>>def cube(x): return x*x*x

>>>map(cube, range(1, 11)) <</span>map object at 0x0000000002C82B70> >>>defadd(x,y): return x+y

>>>reduce(add, range(1, 11)) Traceback (most recent call last): File "", line 1, in<</span>module> reduce(add, range(1, 11)) NameError: name 'reduce' is not defined

这种情况是因为在3.3里面,map(),filter()这些的返回值已经不再是list,而是iterators, 所以想要使用,只用将iterator 转换成list 即可, 比如  list(map())

而reduce已经取消了,如想使用,可以用fuctools.reduce来调用。但是要先导入fuctools, 即输入:import fuctools

e.g1

>>>
sentence = 'It is raining cats and dogs'

>>>
words = sentence.split()


>>>
print words


['It', 'is', 'raining', 'cats', 'and', 'dogs']


>>>


>>>
lengths = map(lambda word: len(word), words)


>>>
print (list(lengths))



[2, 2, 7, 4, 3, 4]

e.g2

>>>import functools

>>>def add(x,y): return x+y ...

>>>functools.reduce(add, range(1, 11)) 55

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