poj 3709 K-Anonymous Sequence 斜率优化dp
2013-07-16 16:58
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因为有k个数的限制,所以要注意出队的时间。
/* */ /* */ /* */ /* */ /* */ /* */ #include<iostream> #include<cstdio> #include<algorithm> using namespace std; #define inf 0x7ffffffffffffffLL long long a[500005]; long long sum[500005]; long long dp[500005]; int q[500005]; int n,k; long long gdp(int i,int j) { return (i-j>=k)?(dp[j]+sum[i]-sum[j]-(i-j)*a[j+1]):(inf); } long long gup(int j,int k) { return dp[j]-dp[k]+sum[k]-sum[j]+(j)*a[j+1]-(k)*a[k+1]; } long long gdown(int j,int k) { return a[j+1]-a[k+1]; } int main() { int cas; scanf("%d",&cas); while(cas--) { scanf("%d%d",&n,&k); sum[0]=0; for(int i=1;i<=n;i++) { scanf("%lld",&a[i]); sum[i]=sum[i-1]+a[i]; } int head=0,tail=0; dp[0]=q[0]=0; for (int i=1;i<=n;i++) { if(i-k>0) { while(head<tail&&gup(q[tail-1],q[tail])*gdown(q[tail],i-k)>=gdown(q[tail-1],q[tail])*gup(q[tail],i-k)) tail--; q[++tail]=i-k; } while(head<tail&&gup(q[head+1],q[head])<=i*gdown(q[head+1],q[head])) head++; dp[i]=gdp(i,q[head]); } printf("%lld\n",dp ); } }
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