『PHP』Invalid argument supplied for foreach 解决办法
2013-03-16 09:04
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QUOTE: foreach($extcredits as $id => $credit) { if($credit['ratio']) { $exchcredits[$id] = $credit; } } 改为 QUOTE: if(is_array($extcredits)) //add { foreach($extcredits as $id => $credit) { if($credit['ratio']) { $exchcredits[$id] = $credit; } } } //add
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