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[LeetCode] Reverse Linked List II

2013-01-24 19:23 411 查看
/**
* Definition for singly-linked list.
* struct ListNode {
*     int val;
*     ListNode *next;
*     ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *reverseBetween(ListNode *head, int m, int n) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
ListNode *phead = new ListNode(0);
phead->next = head;
ListNode *prev = phead;
ListNode *curr = head;

int i;
for (i = 1; i < m; i++) {
prev = curr;
curr = curr->next;
}

ListNode *mp = prev;
ListNode *np = curr;

while (i <= n) {
ListNode *next = curr->next;
curr->next = prev;
prev = curr;
curr = next;
i++;
}

mp->next = prev;
np->next = curr;

return phead->next;
}
};


Small Case: 0ms

Large Case: 8ms

Time: O(n)

Space: O(1)

设置一个指向头指针的指针对简化代码非常有益,可以省去很多特殊条件的判断
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