sum of all integer numbers
2012-12-09 15:39
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sum of all integer numbers
时间限制：1000 ms | 内存限制：65535 KB难度：0
描述 Your task is to find the sum of all integer numbers lying between 1 and
N inclusive.
输入 There are multiple test cases.
The input consists of a single integer N that is not greater than 10000 by it's absolute value.
输出 Write a single integer number that is the sum of all integer numbers lying between 1 and N inclusive.
样例输入
3
样例输出
6
代码
#include<stdio.h>
int main(void)
{
int n;
while(scanf("%d",&n)!=EOF)
{
if(n>0)
printf("%d\n", (n+1)*n/2);
else
printf("%d\n", 1-n*(n-1)/2);
}
return 0;
}
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