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[SVG] 根据SVG椭圆弧路径参数计算中心点坐标、起始角度、结束角度的Javascript函数

2012-09-08 16:12 1021 查看
SVG spec 1.2以及之前的版本标准中,都只有一种绘制椭圆弧的方式,即以起点、终点、长半轴、短半轴、大小弧标记、顺逆时针方向标记、倾角为参数来确定一段弧。这个方法很强大并灵活,可绘制任意的椭圆弧。有时候我们需要计算圆弧的圆心和起始角度、结束角度,虽然标准官方文档给出了计算公式的描述,但是没有给出直接的代码。我根据标准文档以及网上的资料,写了一个Javascript函数来做这件事。
根据SVG椭圆弧路径参数计算中心点坐标、起始角度、结束角度的Javascript函数:

function radian( ux, uy, vx, vy ) {
var dot = ux * vx + uy * vy;
var mod = Math.sqrt( ( ux * ux + uy * uy ) * ( vx * vx + vy * vy ) );
var rad = Math.acos( dot / mod );
if( ux * vy - uy * vx < 0.0 ) {
rad = -rad;
}
return rad;
}

    // svg : [A | a] (rx ry x-axis-rotation large-arc-flag sweep-flag x y)+
    // x1 y1 rx ry φ fA fS x2 y2
    // sample :  svgArcToCenterParam(200,200,50,50,0,1,1,300,200)
function svgArcToCenterParam(x1, y1, rx, ry, phi, fA, fS, x2, y2) {
var cx, cy, startAngle, deltaAngle, endAngle;
var PIx2 = Math.PI * 2.0;

if (rx < 0) {
rx = -rx;
}
if (ry < 0) {
ry = -ry;
}
if (rx == 0.0 || ry == 0.0) { // invalid arguments
throw Error('rx and ry can not be 0');
}

var s_phi = Math.sin(phi);
var c_phi = Math.cos(phi);
var hd_x = (x1 - x2) / 2.0; // half diff of x
var hd_y = (y1 - y2) / 2.0; // half diff of y
var hs_x = (x1 + x2) / 2.0; // half sum of x
var hs_y = (y1 + y2) / 2.0; // half sum of y

// F6.5.1
var x1_ = c_phi * hd_x + s_phi * hd_y;
var y1_ = c_phi * hd_y - s_phi * hd_x;

// F.6.6 Correction of out-of-range radii
// Step 3: Ensure radii are large enough
var lambda = (x1_ * x1_) / (rx * rx) + (y1_ * y1_) / (ry * ry);
if (lambda > 1) {
rx = rx * Math.sqrt(lambda);
ry = ry * Math.sqrt(lambda);
}

var rxry = rx * ry;
var rxy1_ = rx * y1_;
var ryx1_ = ry * x1_;
var sum_of_sq = rxy1_ * rxy1_ + ryx1_ * ryx1_; // sum of square
if (!sum_of_sq) {
throw Error('start point can not be same as end point');
}
var coe = Math.sqrt(Math.abs((rxry * rxry - sum_of_sq) / sum_of_sq));
if (fA == fS) { coe = -coe; }

// F6.5.2
var cx_ = coe * rxy1_ / ry;
var cy_ = -coe * ryx1_ / rx;

// F6.5.3
cx = c_phi * cx_ - s_phi * cy_ + hs_x;
cy = s_phi * cx_ + c_phi * cy_ + hs_y;

var xcr1 = (x1_ - cx_) / rx;
var xcr2 = (x1_ + cx_) / rx;
var ycr1 = (y1_ - cy_) / ry;
var ycr2 = (y1_ + cy_) / ry;

// F6.5.5
startAngle = radian(1.0, 0.0, xcr1, ycr1);

// F6.5.6
deltaAngle = radian(xcr1, ycr1, -xcr2, -ycr2);
while (deltaAngle > PIx2) { deltaAngle -= PIx2; }
while (deltaAngle < 0.0) { deltaAngle += PIx2; }
if (fS == false || fS == 0) { deltaAngle -= PIx2; }
endAngle = startAngle + deltaAngle;
while (endAngle > PIx2) { endAngle -= PIx2; }
while (endAngle < 0.0) { endAngle += PIx2; }

var outputObj = { /* cx, cy, startAngle, deltaAngle */
cx: cx,
cy: cy,
startAngle: startAngle,
deltaAngle: deltaAngle,
endAngle: endAngle,
clockwise: (fS == true || fS == 1)
}

return outputObj;
}用法示例:
SVG: <path d="M 0 100 A 60 60 0 0 0 100 0"/>JS: var result = svgArcToCenterParam(0, 100, 60, 60, 0, 0, 0, 100, 0);
console.log(result);将得到如下返回结果: {
cx: 49.99999938964844,
cy: 49.99999938964844,
startAngle: 2.356194477985314,
deltaAngle: -3.141592627780225,
endAngle: 5.497787157384675,
clockwise: false
}以上实现代码最早公布于2012年,但有bug,某些用例下无法得到正确结果,现已修正。如有疑问,可以留言给我。
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