您的位置:首页 > 其它

第九周任务1(Complex类中的<<和>>运算符的重载)

2012-04-16 17:20 411 查看
/*(文件注释头部开始)

*程序的版权和版本声明部分

*Copyright (c) 2011,烟台大学计算机学院学生

*All rights reserved.

*文件名称:Complex类中的<<和>>运算符的重载

*作    者:王智凯

*完成日期:2011年4月16号

*版本号:凯子

* 对任务及求解方法的描述部分

* 输入描术:

* 问题描述:在重载运算符+、-、*、/的基础上,增加重载运算符>>  << ,实现输入和输出。

* 程序输出:

* 程序头部的注释结束

*/ 

 

#include <iostream>

#include <iomanip>

using namespace std;

class Complex
{
public:
Complex(){real = 0; imag = 0;}
Complex(double r){real = r;imag = 0;}//类型转换函数
Complex(double r,double i){real = r; imag = i;}
friend Complex operator+ (Complex c1,Complex c2);
friend Complex operator- (Complex c1, Complex c2);
friend Complex operator- (Complex &c);
friend Complex operator* (Complex c1, Complex c2);
friend Complex operator/ (Complex c1, Complex c2);
friend ostream& operator << (ostream &,Complex &);
friend istream& operator >> (istream &,Complex &);
private:
double real;
double imag;
};

Complex operator+ (Complex c1, Complex c2)
{
return Complex(c1.real + c2.real, c1.imag + c2.imag);
}

Complex operator- (Complex c1, Complex c2)
{
return Complex(c1.real - c2.real, c1.imag - c2.imag);
}

Complex operator - (Complex &c)
{
return Complex(-c.real, -c.imag);
}

Complex operator* (Complex c1, Complex c2)
{
return Complex(c1.real * c2.real - c1.imag * c2.imag, c1.imag * c2.real + c1.real * c2.imag);
}

Complex operator/ (Complex c1, Complex c2)
{
return Complex((c1.real * c2.real + c1.imag * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag), (c1.imag * c2.real - c1.real * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag));
}
ostream& operator << (ostream &ouput,Complex &c)
{
ouput << "(" << setprecision(3) << c.real;
if(c.imag >= 0)
ouput << "+";
ouput << setprecision(3) << c.imag << "i)" << endl;
return ouput;
}

istream& operator >> (istream &input, Complex &c)
{
char c1;
cout << "input real part and imaginary part of complex number:";
input >> c.real >> c.imag;
return input;
}

int main()
{
double d = 3;
Complex c1, c2, c3;
cin >> c1;
cout << "c1 = " << c1;

cin >> c2;
cout << "c2 = " << c2;

c3 = c1 + c2;
cout << "c1 + c2 = " << c3;

c3 = c1 + d;
cout << "c1 + " << d << "= " << c3;

c3 = d + c1;
cout << d << " + c1" << "= " << c3;

c3 = c1 - c2;
cout << "c1 - c2 = " << c3;

c3 = c1 - d;
cout << "c1 - " << d << "= " << c3;

c3 = d - c1;
cout << d << " - c1" << "= " << c3;

c3 = - c1;
cout << " -c1= " << c3;

c3 = c1 * c2;
cout << "c1 * c2 = " << c3;

c3 = c1 * d;
cout << "c1 * " << d << "= " << c3;

c3 = d * c1;
cout << d << " * c1" << "= " << c3;

c3 = c1 / c2;
cout << "c1 / c2 = " << c3;

c3 = c1 / d;
cout << "c1 / " << d << "= " << c3;

c3 = d / c1;
cout << d << " / c1" << "= " << c3;

system("pause");
return 0;
}

 



 

上机感言:其实用重载流运算符挺方便的 
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  任务 c input system
相关文章推荐