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顺时针螺旋法则(clockwise/spiral rule)教你认变量类型

2011-11-26 10:07 573 查看
The ``Clockwise/Spiral Rule''

“顺时针螺旋法则”

By David Anderson

作者:David Anderson

There is a technique known as the ``Clockwise/Spiral Rule'' which enables any C programmer to parse in their head any C declaration!

这个技巧称为“顺时针螺旋法则”。C程序员们用了它,就可以看懂任何C语言变量类型声明。

There are three simple steps to follow:

一共三步,如下:

Starting with the unknown element, move in a spiral/clockwise direction; when ecountering the following elements replace them with the corresponding english statements:

从变量名开始,沿着顺时针螺旋移动。每次遇到以下这几种符号,把它换成相对应的汉语句子:

[X] or []

=> Array X size of... or Array undefined size of...

-> ...类型的长度为X的数组, 或者 ...类型的长度未知的数组

(type1, type2)

=> function passing type1 and type2 returning...

-> 传入type1和type2类型,返回...类型的函数。

*

=> pointer(s) to...

-> 指向...类型的指针

【译注:英语怎么都是前缀表达式?郁闷。谁帮我把汉语也改成前缀或者后缀表达式吧。

Keep doing this in a spiral/clockwise direction until all tokens have been covered.

不断地沿着顺时针螺旋方向做上述动作,直到所有的符号都遍历到。

Always resolve anything in parenthesis first!

遇到括号,一定要先确定括号内的类型。

Example #1: Simple declaration

例1: 简单声明

+-------+

| +-+ |

| ^ | |

char *str[10];

^ ^ | |

| +---+ |

+-----------+

Question we ask ourselves: What is str?

问题:str是什么类型?

``str is an...

“str的类型是...

We move in a spiral clockwise direction starting with `str' and the first character we see is a `[' so, that means we have an array, so...

我们沿着顺时针螺旋移动。从 “str”开始,遇到的第一个符号是 “[”。所以,它是个数组。 所以……

``str is an array 10 of...

“str是一个容纳……类型的长度为10的数组

Continue in a spiral clockwise direction, and the next thing we encounter is the `*' so, that means we have pointers, so...

继续沿着顺时针螺旋移动。下一个遇到的符号是`*'。这是指针的意思。所以……

``str is an array 10 of pointers to...

“str是一个容纳指向……的指针的长度为10的数组

Continue in a spiral direction and we see the end of the line (the `;'), so keep going and we get to the type `char', so...

继续沿着顺治真螺旋移动。遇到了行末(其实就是分号“;”),不管它,继续移动,我们遇到了“char”。所以……

``str is an array 10 of pointers to char''

“str是一个容纳指向char类型的指针的长度为10的数组。”

We have now ``visited'' every token; therefore we are done!

我们已经“遍历”了每个符号。所以,完成了!

Example #2: Pointer to Function declaration

例2:指向函数的指针的声明

+--------------------+

| +---+ |

| |+-+| |

| |^ || |

char *(*fp)( int, float *);

^ ^ ^ || |

| | +--+| |

| +-----+ |

+------------------------+

Question we ask ourselves: What is fp?

问题:fp是什么类型?

``fp is a...

“fp是一个……

Moving in a spiral clockwise direction, the first thing we see is a `)'; therefore, fp is inside parenthesis, so we continue the spiral inside the parenthesis and the next character seen is the `*', so...

沿着顺时针螺旋移动,第一个遇到的是右括号“)”。我们发现,fp被放在一个括号内。我们必须先留在括号内,继续沿着螺旋移动。下一个遇到的符号是“*”。所以……

``fp is a pointer to...

“fp是一个指向……的指针

We are now out of the parenthesis and continuing in a spiral clockwise direction, we see the `('; therefore, we have a function, so...

我们现在离开了括号。继续沿着顺时针螺旋移动。我们遇到“(”。这是函数的意思。所以……

``fp is a pointer to a function passing an int and a pointer to float returning...

“fp是一个指向一个参数为一个int和一个指向float型的指针,返回值是……型的函数的指针。

Continuing in a spiral fashion, we then see the `*' character, so...

继续绕圈。遇到了“*”,所以……

``fp is a pointer to a function passing an int and a pointer to float returning a pointer to...

“fp是一个指向一个参数为一个int和一个指向float型的指针,返回值是一个指向……的指针的函数的指针。

Continuing in a spiral fashion we see the `;', but we haven't visited all tokens, so we continue and finally get to the type `char', so...

继续绕圈,遇到“;”,但是符号还没遍历完。继续绕圈,最后遇到char。所以……

``fp is a pointer to a function passing an int and a pointer to float returning a pointer to a char''

“fp是一个指向一餐参数为一个int和一个指向float型的指针,返回值是一个指向char的指针的函数的指针。”

Example #3: The ``Ultimate''

例3:终极难题

+-----------------------------+

| +---+ |

| +---+ |+-+| |

| ^ | |^ || |

void (*signal(int, void (*fp)(int)))(int);

^ ^ | ^ ^ || |

| +------+ | +--+| |

| +--------+ |

+----------------------------------+

Question we ask ourselves: What is `signal'?

问题:signal是什么类型?

Notice that signal is inside parenthesis, so we must resolve this first!

首先,必须意识到signal在括号内。所以必须先解决括号内的类型。

Moving in a clockwise direction we see `(' so we have...

沿着顺时针移动,遇到“(”,所以……

``signal is a function passing an int and a...

“signal是一个参数为一个int和一个……型变量,返回值是……的函数。

Hmmm, we can use this same rule on `fp', so... What is fp? fp is also inside parenthesis so continuing we see an `*', so...

吼吼,我们可以用同样的规则确定fp的类型。所以……fp是什么类型呢?fp也在括号内。所以,继续绕圈,我们遇见“*”。所以……

fp is a pointer to...

fp是一个指向……的指针

Continue in a spiral clockwise direction and we get to `(', so...

继续绕圈,遇到“(”。所以……

``fp is a pointer to a function passing int returning...''

“fp是一个指向一个参数为int,返回值是……的函数的指针。”

Now we continue out of the function parenthesis and we see void, so...

离开函数参数的括号,我们遇见void。所以……

``fp is a pointer to a function passing int returning nothing (void)''

“fp是一个指向参数为int,什么也不返回(返回void)的函数的指针。”

We have finished with fp so let's catch up with `signal', we now have...

fp部分结束了。我们回到signal的类型。目前是……

``signal is a function passing an int and a pointer to a function passing an int returning nothing (void) returning...

“signal是一个参数为一个int和一个指向一个参数为int,什么也不返回的函数的指针,返回值为……的函数。”

We are still inside parenthesis so the next character seen is a `*', so...

我们还在括号内。下一个符号是“*”。所以

``signal is a function passing an int and a pointer to a function passing an int returning nothing (void) returning a pointer to...

“signal是一个参数位一个int和一个指向一个参数为int,什么也不返回的函数的指针,返回值为指向……的指针的函数。”

We have now resolved the items within parenthesis, so continuing clockwise, we then see another `(', so...

现在,括号内的类型已经解决了。继续绕圈,遇到另一个“(”。所以……

``signal is a function passing an int and a pointer to a function passing an int returning nothing (void) returning a pointer to a function passing an int returning...

“signal是一个参数位一个int和一个指向一个参数为int,什么也不返回的函数的指针,返回值为指向一个参数为int,返回值为……的函数的指针的函数。”

Finally we continue and the only thing left is the word `void', so the final complete definition for signal is:

最后,继续绕圈。最后一个符号就是最左边的“void”。所以,signal的最终定义就是:

``signal is a function passing an int and a pointer to a function passing an int returning nothing (void) returning a pointer to a function passing an int returning nothing (void)''

“signal是一个参数位一个int和一个指向一个参数为int,什么也不返回的函数的指针,返回值为指向一个参数为int,什么也不返回的函数的指针的函数。”

The same rule is applied for const and volatile. For Example:

同样的规则,const和volatile关键字也有用。比如:

const char *chptr;

Now, what is chptr??

那么,chptr是什么类型??

``chptr is a pointer to a char constant''

“chptr是一个指向char型常量的指针变量。”

How about this one:

下面这个呢:

char * const chptr;

Now, what is chptr??

现在,chptr又是什么??

``chptr is a constant pointer to char''

“chptr是一个指向char型变量的指针常量。”

Finally:

最后一题:

volatile char * const chptr;

Now, what is chptr??

现在,chptr又是什么类型??

``chptr is a constant pointer to a char volatile.''

“chptr是一个指向char volatile型变量的指针常量。”

Practice this rule with the examples found in K&R II on page 122.

你可以做一个练习,用上述规则做《K&R的C语言书(第二版)》第122页上的例子。

Copyright © 1993,1994 David Anderson
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