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单链表 快速排序

2011-09-07 17:58 323 查看
通过移动链表指针实现单链表快排:

#include <iostream>
using namespace std;

struct Node
{
int data;
Node* next;
};

Node* InitLinkList(int arr[],int N)
{
if(N < 1)
return NULL;
Node *p = new Node,*head = p;
p->data = arr[0];
p->next = NULL;
for(int i=1; i<N; ++i)
{
p->next = new Node;
p = p->next;
p->data = arr[i];
p->next = NULL;
}
return head;
}

void print(Node* head)
{
while (head)
{
cout<<head->data;
head = head->next;
if (head)
{
cout<<"->";
}
}
cout<<endl;
}

Node* Partion(Node* front, Node* head, Node* tail)
{
if (!head)
{
return NULL;
}
Node* tempHead = head;
Node* prev = head;
Node* cur = head->next;
while (cur != tail)
{
if (cur->data < head->data)
{
Node* temp;
prev->next = cur->next;
cur->next = tempHead;
tempHead = cur;
cur = prev->next;
}else
{
prev = prev->next;
cur = cur->next;
}
}
if (front)
{
front->next = tempHead;
}
return tempHead;
}

Node* QuickSort(Node* front, Node* head, Node* tail)
{
if (!head || !head->next || head->next == tail || head == tail)
{
return head;
}
Node* tempHead = Partion(front, head, tail);
Node* resultHead = QuickSort(front, tempHead, head);
QuickSort(head, head->next, tail);

return resultHead;
}

int main()
{
int Arra[13]={5,20,14,1, 8, 11, 2, 6, 9, 2, 4, 17, 13};
Node* head = InitLinkList(Arra, 13);

print(head);
head = QuickSort(NULL, head, NULL);
print(head);

return 0;
}
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