【叶子函数分享十二】根据身份证得到生日函数

go

--创建函数(函数来自csdn，作者不详)

create function [dbo].[Get_birthday]

(

@idcardno nvarchar(50)

)

returns varchar(10)

as

begin

declare @birthday datetime

if (len(@idcardno)=15 or len(@idcardno)=16) and substring(@idcardno,9,2) between 1 and 12 and substring(@idcardno,11,2) between 1 and 31

set @birthday= convert(varchar(10),'19'+substring(@idcardno,7,2)+'-'+substring(@idcardno,9,2)+'-'+substring(@idcardno,11,2),120)

else if len(@idcardno)=18 and substring(@idcardno,7,2)>=19 and substring(@idcardno,11,2) between 1 and 12 and substring(@idcardno,13,2) between 1 and 31

set @birthday= convert(varchar(10),substring(@idcardno,7,4)+'-'+substring(@idcardno,11,2)+'-'+substring(@idcardno,13,2),120)

else

set @birthday=null

return(convert(varchar(10),@birthday,120))

end

--测试示例

select dbo.[Get_birthday]('222222198306043213')

--运行结果

/*

1983-06-04

*/

本文来自CSDN博客，转载请标明出处：http://blog.csdn.net/maco_wang/archive/2011/03/19/6261536.aspx