【叶子函数分享十二】根据身份证得到生日函数

go
--创建函数(函数来自csdn，作者不详)
create function [dbo].[Get_birthday]
(
    @idcardno nvarchar(50)
)
returns varchar(10)
as
begin
    declare @birthday datetime
 
if (len(@idcardno)=15 or len(@idcardno)=16) and substring(@idcardno,9,2) between 1 and 12   and substring(@idcardno,11,2) between 1 and 31
 set @birthday= convert(varchar(10),'19'+substring(@idcardno,7,2)+'-'+substring(@idcardno,9,2)+'-'+substring(@idcardno,11,2),120)
else if len(@idcardno)=18 and substring(@idcardno,7,2)>=19 and substring(@idcardno,11,2) between 1 and 12   and substring(@idcardno,13,2) between 1 and 31
 set @birthday= convert(varchar(10),substring(@idcardno,7,4)+'-'+substring(@idcardno,11,2)+'-'+substring(@idcardno,13,2),120)
else
 set @birthday=null
 return(convert(varchar(10),@birthday,120))
end
 
--测试示例
select dbo.[Get_birthday]('222222198306043213')
 
--运行结果
/*
1983-06-04
*/