HDU 2055 An easy problem
2011-01-29 13:41
232 查看
继续水水
#include <stdio.h> int main ( ) { int n; scanf ( "%d" , &n ); while ( n-- ) { int x,y; char ch; scanf ( "%*c%c%d",&ch,&x );//别忘了把回车吃掉 if ( ch <= 'Z' ) y = x + ch - 'A' + 1;//别忘了加1 else y = x - ( ch - 'a' + 1 ); printf ( "%d\n" , y ); } return 0; }
相关文章推荐
- HDU-2055( An easy problem )
- HDU 2055 An easy problem
- HDU:2055 An easy problem
- hdu-2055-An easy problem
- HDU 2055 An easy problem
- hdu 2055 An easy problem
- HDU 2055 An easy problem(关于这道题中的一些小问题希望大家了解)
- HDU 2055 An easy problem
- HDU 2055 An easy problem
- HDU 2055 An easy problem
- hdu 2055 An easy problem (水题)
- hdu 2055 An easy problem (java)
- HDU 2055 An easy problem
- hdu 2055 An easy problem (java)
- hdu 2055 An easy problem (水题)
- 【暑期基础3】C HDU 2055 An easy problem
- HDU 2055 An easy problem
- hdu 2055 An easy problem
- HDU 2055 An easy problem
- HDU 2055 An easy problem